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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Specific Heat Capacities of Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Specific Heat Capacities of Gases

A sample of an ideal gas ( C_p / C_V = γ ) has an initial pressure...

A sample of an ideal gas (Cp/CV=γC_p / C_V = \gamma) has an initial pressure p0p_0 and volume V0V_0. The gas is isothermally taken to a pressure p0/2p_0 / 2 and from there adiabatically to a pressure p0/4p_0 / 4. Determine the final volume.

Options

  1. A41/γV04^{1/\gamma} V_0
  2. B2(γ+1)/γV02^{(\gamma + 1)/\gamma} V_0
  3. C4V04 V_0
  4. D2(γ−1)/γV02^{(\gamma - 1)/\gamma} V_0

Correct answer

B. 2(γ+1)/γV02^{(\gamma + 1)/\gamma} V_0

Step-by-step solution

For the isothermal process, the temperature remains constant, so pV=constantp V = \text{constant}.

Let the volume after the isothermal process be V1V_1.

p0V0=(p02)V1p_0 V_0 = \left(\dfrac{p_0}{2}\right) V_1

V1=2V0V_1 = 2 V_0

For the subsequent adiabatic process, pVγ=constantp V^{\gamma} = \text{constant}.

Let the final volume be V2V_2.

p1V1γ=p2V2γp_1 V_1^{\gamma} = p_2 V_2^{\gamma}

\left(\dfrac{p_0}{2}\right) (2 V_0)^{\gamma} = \left(\dfrac{p_0}{4}\right) V_2^{\gamma}<br><br><br><br>\dfrac{1}{2} \times 2^{\gamma} V_0^{\gamma} = \dfrac{1}{4} V_2^{\gamma}<br><br><br><br>V_2^{\gamma} = 4 \times \dfrac{1}{2} \times 2^{\gamma} V_0^{\gamma}<br><br><br><br>V_2^{\gamma} = 2 \times 2^{\gamma} V_0^{\gamma}<br><br><br><br>V_2^{\gamma} = 2^{\gamma + 1} V_0^{\gamma}<br><br><br><br>V_2 = 2^{(\gamma + 1)/\gamma} V_0
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