JEE Main202331 Jan 2023Morning ShiftChemistryHydrogenActual
H 2 O 2 acts as a reducing agent in
Options
- A2 NaOCl + H 2 O 2 → 2 NaCl + H 2 O + O 2
- B2 Fe 2 + + 2 H + + H 2 O 2 → 2 Fe 3 + + 2 H 2 O
- CMn 2 + + 2 H 2 O 2 → MnO 2 + 2 H 2 O
- DNa 2   S + 4 H 2 O 2 → Na 2 SO 4 + 4 H 2 O
Correct answer
A. 2 NaOCl + H 2 O 2 → 2 NaCl + H 2 O + O 2
Step-by-step solution
Here, the H 2 O 2 act as the reducing agent, as the Cl has +1 oxidation state of in NaOCl and after reaction with the H 2 O 2 , in the presence of the acid, it reduces the Cl in NaOCl to Cl - having -1 oxidation state. So, as Cl oxidation state decreases from the +1 to -1 oxidation state, hence the H 2 O 2 is acting as the reducing agent.