The products obtained during treatment of hard water using Clark's...

The products obtained during treatment of hard water using Clark's method are

Options

A ${CaCO}_{3}$ and ${MgCO}_{3}$
B $Ca{\left(OH\right)}_{2}$ and $Mg{\left(OH\right)}_{2}$
C{CaCO}_{3} $and$ Mg{ $\left(OH\right)}_{2}$
DCa{ $\left(OH\right)}_{2}$ and ${MgCO}_{3}$

Correct answer

C. {CaCO}_{3} $and$ Mg{ $\left(OH\right)}_{2}$

Step-by-step solution

In this method calculated amount of lime is added to hard water. It precipitates out calcium carbonate and magnesium hydroxide which can be filtered off In Clark's method lime water is used.
It is because of low solubility product of Mg(OH)₂ as compared to that of MgCO_3.
$Ca{\left({HCO}_{3}\right)}_{2} + 2Ca{\left(OH\right)}_{2} \to 2{CaCO}_{3} + 2{H}_{2}O$
$Mg{\left({HCO}_{3}\right)}_{2} + 2Ca{\left(OH\right)}_{2} \to 2{CaCO}_{3} + Mg{\left(OH\right)}_{2} + 2{H}_{2}O$

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