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Concepts Of Physics MCQ Edition [Volume 2]PhysicsPhotoelectric Effect and Wave–Particle Duality

An electron and a proton are accelerated through an identical potential difference. Let _e and _p represent the de Broglie wavelengths of the electron and the proton, respectively.

Options

  1. A_e < _p
  2. B_e = _p
  3. C_e > _p
  4. DThe relationship between _e and _p depends on the accelerating potential difference.

Correct answer

C. _e > _p

Step-by-step solution

The de Broglie wavelength of a particle accelerated through a potential difference V is given by = h 2mqV . For an electron and a proton, the magnitude of the charge q and the accelerating potential difference V are identical. This implies that 1 m . Since the mass of an electron is much less than the mass of a proton ( m_e Therefore, _e > _p .

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