Boiling of hard water is helpful in removing the temporary hardness...

Boiling of hard water is helpful in removing the temporary hardness by converting calcium hydrogen carbonate and magnesium hydrogen carbonate to

Options

A{CaCO}_{3} $and$ Mg{ $\left(OH\right)}_{2}$
B
${CaCO}_{3}$ and ${MgCO}_{3}$
CCa{ $\left(OH\right)}_{2}$ and ${MgCO}_{3}$
D $Ca{\left(OH\right)}_{2}$ and $Mg{\left(OH\right)}_{2}$

Correct answer

A. {CaCO}_{3} $and$ Mg{ $\left(OH\right)}_{2}$

Step-by-step solution

During boiling $Mg{\left({\text{ HCO }}_{3}\right)}$ _{2} $is converted to insoluble$ Mg{\left(OH\right)}_{2} $$ Mg{\left({HCO}_{3}\right)}_{2}\overset{Boiling}{\to}Mg{\left(OH\right)}_{2} ↓ + 2{CO}_{2} $$ Ca{\left({HCO}_{3}\right)}_{2}\overset{boiling}{\to}{CaCO}_{3} ↓ + {H}_{2}O + {CO}_{2} $$ Ca{\left({HCO}_{3}\right)}_{2} $changes to insoluble$ {CaCO}_{3}

Mg(OH)₂ is less soluble than MgCO_3.Hence, the products formed are CaCO₃ and Mg(OH)₂.

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