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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrogen

JEE Main 2020 · 7 January · Morning Shift · Chemistry · Hydrogen

In comparison to the zeolite process for the removal of permanent...

In comparison to the zeolite process for the removal of permanent hardness, the synthetic resin method is

Options

  1. Aless efficient as it exchanges only anions.
  2. Bmore efficient as it can exchange both cations as well as anions.
  3. Cless efficient as the resins cannot be regenerated.
  4. Dmore efficient as it can exchange only cations.

Correct answer

B. more efficient as it can exchange both cations as well as anions.

Step-by-step solution

Zeolite removes only cations from hard water, as given below by reaction:

2NaZ+M+2(aq)→MZ2+2Na+HereM−Ca,Mg2NaZ + {M}^{+ 2} ( aq ) \to {MZ}_{2} + 2{Na}^{+}HereM - Ca, Mg

While, synthetic resin removes both cations and anions, as given by following reactions:

For cations-

2RNa(s)+M+2(aq)→R2M(s)+2Na+(aq)2RNa ( s ) + {M}^{+ 2} ( aq ) \to {R}_{2}M ( s ) + 2{Na}^{+} ( aq )

For anions-

RNH3+OH−(s)+X−(aq)→RNH3+X−(s)+OH−(aq){RNH}_{3}^{+}{OH}^{-} ( s ) + {X}^{-} ( aq ) \to {RNH}_{3}^{+}{X}^{-} ( s ) + {OH}^{-} ( aq )

So, synthetic resin method is more efficient as it can exchange both cations as well anions.

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