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JEE Main 20198 AprilMorning Shift

Exam: JEE Main
Year: 2019
Date: 8 April
Shift: Morning Shift
Subject: Chemistry
Chapter: Hydrogen

JEE Main 2019 · 8 April · Morning Shift · Chemistry · Hydrogen

100mL of a water sample contains 0.81g of calcium bicarbonate and...

100mL

of a water sample contains

0.81g

of calcium bicarbonate and

0.73

g of magnesium bicarbonate. The hardness of this water sample expressed in terms of equivalents of

CaC{O}_{3}

is:
(molar mass of calcium bicarbonate is

162gmmo{l}^{- 1}

and magnesium bicarbonate is

146gmo{l}^{- 1} )

Options

A $100ppm$
B $1,000ppm$
C $5,000ppm$
D $10,000ppm$

Correct answer

D. $10,000ppm$

Step-by-step solution

{n}_{eq}CaC{O}_{3} = {n}_{eq}Ca{\left(HC{O}_{3}\right)}_{2} + {n}_{eq}Mg{\left(HC{O}_{3}\right)}_{2}

or,

\dfrac{W}{100} \times 2 = \dfrac{0.81}{162} \times 2 + \dfrac{0.73}{146} \times 2

∴ W = 1.0

∴

Hardness

= \dfrac{1.0}{100} \times {10}^{6} = 10000ppm

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