JEE Main202329 Jan 2023Evening ShiftChemistryIonic EquilibriumActual
The volume of HCl , containing 73 g L - 1 , required to completely neutralise NaOH obtained by reacting 0 . 69 g of metallic sodium with water, is _____ mL . (Nearest Integer) (Given : molar Masses of Na , Cl , O , H are 23 , 35 . 5 , 16 and 1 g mol - 1 respectively)
Correct answer
0
Step-by-step solution
Mole of NaOH = 0 . 69 23 = 3 × 10 - 2 2 Na + 2 H 2 O ⟶ 2 NaOH + H 2 Number of moles of Na = Number of moles of NaOH NaOH   +   HCl   →   NaCl   +   H 2 O Moles of HCl = moles of NaOH ⇒   ( Molarity   ×   V ) HCl   =   Number of moles of NaOH ⇒   73 36 . 5   ×   1   ×   V   =   0 . 03 ⇒ V   =   15   ×   10 - 3   Lit ⇒   V   =