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If the eccentricity of the hyperbola x²-y² cosec ² =25 is 5 times the eccentricity of the ellipse x² cosec ² +y²=5 then is equal to :

Options

  1. A⁻¹ 2
  2. B⁻¹ 3 4
  3. C⁻¹ 2 5
  4. D⁻¹ 2 5

Correct answer

A. ⁻¹ 2

Step-by-step solution

Eccentrcity of x² 25 - y² 25 ² =1 is 1+ ² Eccentricity of x² 5 ² + y² 5 =1 is 1- ² Given, 1+ ² = 5 1- ² array l ² = 2 3 = ⁻¹ 2 3 = ⁻¹ 2 array

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