Highly selective Backlog Qs for JEE MainMathematicsHyperbola
The equation of the hyperbola having eccentricity 2 , such that the distance between its foci is 8 and the major axis is along the x -axis, while the minor axis is along the   y -axis, is
Options
- Ax 2 12 - y 2 4 = 1
- Bx 2 4 - y 2 12 = 1
- Cx 2 8 - y 2 2 = 1
- Dx 2 16 - y 2 9 = 1
Correct answer
B. x 2 4 - y 2 12 = 1
Step-by-step solution
Distance between foci = 8 = 2 a e But e = 2 . Therefore, 2 a = 4 ⇒ a = 2 ⇒ a 2 = 4 And b 2 = a 2 e 2 - 1 = 4 4 - 1 = 12 ∴ Equation of hyperbola is x 2 4 - y 2 12 = 1