Highly selective Backlog Qs for JEE MainPhysicsRotational Motion
A uniform cube of side a and mass m rests on a rough horizontal table. A horizontal force F is applied normal to one of the faces at a point that is directly above the centre of the face, at a height 3 a / 4 above the base. The minimum value of F for which the cube begins to topple an edge is (assume that cube does not slide)
Options
- Amg 3
- Bmg 2
- C2 mg 3
- D3 mg 4
Correct answer
C. 2 mg 3
Step-by-step solution
For toppling about edge x x At the moment of toppling the normal force pass through axis xx '. F _ 3 a 4 = mg a 2 or F _ = 2 mg 3