Highly selective Backlog Qs for JEE MainPhysicsRotational Motion
The y – coordinate of centre of mass of a thin and uniform semicircular ring of radius r shown in figure is
Options
- Ar 2
- B2 r π
- Cr 2 π
- D4 r 3 π
Correct answer
B. 2 r π
Step-by-step solution
The wire is uniform. So, the mass per unit length of the wire μ = M π r . Let us assume a small element on the semicircular ring as shown in the figure. Mass of the element d m = M π r r d θ = M π d θ The y -coordinate of the centre of mass y cm = 1 M ∫ y d m ⇒   y cm = 1 M ∫ 0 π r sin θ M π d θ ⇒   y cm = r π 1 + 1 ⇒   y cm = 2 r π