Highly selective Backlog Qs for JEE MainPhysicsThermodynamics
One mole of an ideal monoatomic gas is heated at a constant pressure from 0^ C to 100^ C . Then the change in the internal enery of the gas is (Given, R=8.32 J mol ⁻¹ K ⁻¹ )
Options
- A0.83 10³ J
- B46 10³ J
- C2.08 10³ J
- D1.25 10³ J
Correct answer
D. 1.25 10³ J
Step-by-step solution
We know that U=n C_ v T array l where aligned T &= (T₂-T₁ ) T₁ &=0^ C =273 K T₂ &=100^ C =373 K n &=1 (monoatomic gas) aligned aligned R=8.32 J mol ⁻ k ⁻¹=1 3 2 R (373-273) =1 3 2 8.32 100=3 8.32 50 aligned array 1248 kJ of =1.25 10³ J