Most Important Selected Qs for JEE AdvancedChemistryElectrochemistry
The Cl ₂ evolve at anode during electrolysis of fused MgCl ₂ which produces 13 g Mg . (Atomic mass of Mg =24.3 ) is
Options
- A11.98 lit
- B0.535 mole
- C37.98 gm
- D1.068 mole
Correct answer
C. 37.98 gm
Step-by-step solution
(No. of gm equivalent of Mg at cathode )= ( . No of gm equivalent of Cl ₂ at Anode ) 13 24.3 / 2 = W _ Cl ₂ 35.5 W _ Cl ₂ =37.98 gm or n _ Cl ₂ =0.535 V _ Cl ₂ =11.98 lit at NTP