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The fraction of current carried by each ion in solution is equal to the ratio of conductivity of the ion in solution to the total conductivity of solution. If in a solution which is 0.1 M in Na ₂ SO ₄ and 0.01 M ^2 H ₂ SO ₄ (assume complete ionisation). [Given _ m of Na ⁺, H ⁺ and SO ₄²⁻ are 50.1 ~S ~cm ^2 ~mol ⁻¹, 349.8 ~S ~cm ^2 ~mol ⁻¹ and 160 ~S ~cm ^2 mol ⁻¹ respectively]. Select the correct statement.

Options

  1. AThe fraction of total current carried by Na ⁺ is more than that of H ⁺
  2. BThe fraction of total current carried by H ⁺ is nore than that of SO ₄²⁻
  3. CThe fraction of total current carried by SO ₄²⁻ is more than that of Na ⁺
  4. DThe fraction of total current carried by each ion is in order SO ₄²⁻ Na ⁺ H ⁺

Correct answer

D. The fraction of total current carried by each ion is in order SO ₄²⁻ Na ⁺ H ⁺

Step-by-step solution

Conductivity due to Na ⁺= 2 0.1 50.1 1000 =0.010 ~s ~cm ⁻¹ Conductivity due to H ⁺= 2 0.01 349.8 1000 =0.0069 ~S ~cm ⁻¹ Conductivity due to SO ₄²⁻= 0.11 160 1000 =0.0176 ~S ~cm ⁻¹ Total conductivity =0.0345 ~S ~cm ⁻¹ Fraction of current carried by each ion Na ⁺= 0.01 0.0345 0.29 H ⁺= 0.0069 0.0345 0.20 SO ₄²⁻= 0.0176 0.0345 0.51

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