The conductivity of V ml 0.1 M NaOH solution is 0.022 ~S ~cm ⁻¹ . When this solution was neutralised with an equal volume ( V ml ) of 0.1 M HCl , the conductivity decreases to 0.0056 ~S ~cm ⁻¹ . A further V ml of the same HCl was added and

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The conductivity of V ml 0.1 M NaOH solution is 0.022 ~S ~cm ⁻¹ . When this solution was neutralised with an equal volume ( V ml ) of 0.1 M HCl , the conductivity decreases to 0.0056 ~S ~cm ⁻¹ . A further V ml of the same HCl was added and the conductivity increased to ' X ' S cm ⁻¹ . The value of _ m of HCl is 400 ~S ~cm ^2 mol ⁻¹ . Assume all measurements to be done at the same temperature. Then based on this infor

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Correct answer: C. The value of X is 0.017

aligned _ m ( NaOH ) & = K C 1000= 0.022 0.1 1000 & =220 ~S ~cm ⁻¹ aligned Upon neutralisation, [ NaCl ]=0.05 M _m= 0.0056 0.05 1000=112 ~S ~cm ⁻¹ On further addition of equal volume of acid, the solution is 0.1 3 M in NaCl and 0.1 3 M in HCl aligned & K _ solution = K _ NaCl + K _ HCl & = ( 0.1 3 112+ 0.1 3 400 ) 10⁻³ & =0.017 ~S ~cm ⁻¹ aligned

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