If electrolysis of 1 M NiSO ₄ is carried with inert electrodes at pH =7 at 25^ C (the pressure of gases are taken 1 bar). E _ Ni ²⁺ / Ni ^ =-0.25 ~V E _ H ₂ O / H ₂ ^ =-0.83 ~V The product of electrolysis at cathode and at anode (initially)

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If electrolysis of 1 M NiSO ₄ is carried with inert electrodes at pH =7 at 25^ C (the pressure of gases are taken 1 bar). E _ Ni ²⁺ / Ni ^ =-0.25 ~V E _ H ₂ O / H ₂ ^ =-0.83 ~V The product of electrolysis at cathode and at anode (initially) are:

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Correct answer: C. O ₂ at anodes

H ⁺+ e ⁻ 1 2 H ₂ E ^ =0.0 ~V E = E _ H ⁻ / H ₂ =- 0.059 1 1 [ H ⁺ ] =-0.059 7=-0.413 So, E _ H ⁺ / H E _ NN ^2 / / NI Ni will deposit at cathode At anode cell reaction 4 OH ⁻ 2 H ₂ O + O ₂+4 e

If electrolysis of 1 M NiSO ₄ is carried with inert electrodes at pH =7 at 25^ C (the pressure of gases are taken 1 bar). E _ Ni ²⁺ / Ni ^ =-0.25 ~V E _ H ₂ O / H ₂ ^ =-0.83 ~V The product of electrolysis at cathode and at anode (initially) are:

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