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Most Important Selected Qs for JEE AdvancedMathematicsHyperbola

The director circle of a hyperbola is x^2+y^2-4 y=0 . One end of the transverse axis is (2,0) then a focus is

Options

  1. A( 3 , 2- 3 )
  2. B(- 3 , 2+ 3 )
  3. C( 6 .2- 6 )
  4. D(- 6 , 2+ 6 )

Correct answer

D. (- 6 , 2+ 6 )

Step-by-step solution

Radius of director circle = a ^2- b ^2 =2 aligned & (2 2 )^2-b^2=4 & b^2=4 e= 3 2 aligned Focus lies on the line x-0 -1 2 = y -2 1 2 at a distance ae units from centre. x-0 - 1 2 = y-2 1 2 = 2 3 (x, y)=( 6 .2- 6 ) or (- 6 , 2+ 6 )

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