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The emf of the cell, M ( s ) M _n X_n(0.01 M ) | M _n X_n(0.1 M ) / M ( s ) is found to be 0.0295 V at 25^ C . If M _n X_n is a soluble salt, find the value of n .

Correct answer

2

Step-by-step solution

nM M _ n _ n ^ n ⁺ + ne ⁻ (at anode) M _ n_e⁺ ⁺+ ne ⁻ 2 M (at cathode) Net all reaction: M _ n_E ^ c⁺ M _ n_A ^ c_A^* 0.0295= 0.059 n M_ n=t ^ .m_n ] .M_ n a x ^m ] n =2

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