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A student has 2 containers and each container has 1 L solution. He tries to form an electrochemical cell that is Pt | H ₂(1 ~atm ) | HA (10⁻⁴ M ) | | H ⁺(0.1 M ) | H ₂(1 ~atm ) | Pt If E.M.F of cell is 0.24 and pKa of HA is X . The value of X is [ 2.303 R T F =0.06 ]

Correct answer

06

Step-by-step solution

aligned & E =- 0.06 2 ~K _ a C (0.1)^2 & 0.24=-0.03 ~K _ a 10⁻² & 8=- K _ a +2 & 6= pK _ a aligned

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