In the electrolysis of KI , I ₂ is formed at the anode by the reaction; 2 I I ₂+2 e ⁻ After the passage of current of 0.5 ampere for 9650 seconds, I ₂ formed required 40 ml of 0.1 M Na ₂ ~S ₂ O ₃ 5 H ₂ O solution in the reaction; I ₂+2 ~S ₂

Question

In the electrolysis of KI , I ₂ is formed at the anode by the reaction; 2 I I ₂+2 e ⁻ After the passage of current of 0.5 ampere for 9650 seconds, I ₂ formed required 40 ml of 0.1 M Na ₂ ~S ₂ O ₃ 5 H ₂ O solution in the reaction; I ₂+2 ~S ₂ O ₃²⁻ S ₄ O ₆²⁻+2 I ⁻ What is the current efficiency?

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Correct answer: 8

Number of moles of hypo aligned & = M V 1000 & = 0.1 40 1000 =4 10⁻³ aligned Number of moles of I ₂=2 10⁻³ Mass of I ₂=2 10⁻³ 254 ~g array r w = i t E 96500 2 10⁻³ 254= i 9650 127 96500 i=0.04 ampere ency = 0.04 0.50 100=8 % array

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