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The e.m.f of cell Zn _ ( s ) | ZnSO ₄ | CuSO ₄ | Cu _ ( s ) at 25^ C is 0.03 V and temperature coefficient of e.m. f is (-1.4 10⁻⁴ ~V ) per degree. Calculate the heat of reaction for the change taking place inside the cell. (mark the answer in KJ / mol )

Correct answer

-13.842

Step-by-step solution

F=96500 C E =0.03 ~V T =273+25=298 ~K n =2 ( dE dT )_ p =-1.4 10⁻⁴ v . per degree As H=n F [T ( d E d T )_ P - E ]=2 96500 [298 (-1.4 10⁻⁴ )-0.03 ]=-13842 ~J / mol =-13.842 KJ / mol

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