Let A= [ array ccc x^3+1 & x+5 & 3 x+2 y+1 & -6 x^2+2 & z-1 2 & 3 & 9 x+6 array ] and |A|=3 If f(x)= tr . (B⁻¹ ) and B= adj (A) , then global maximum value of f(x) in x [0,6] is:

Step-by-step solution

aligned B & = adj (A) B=|A| adj A |A| B=|A| A⁻¹ B & =3 A⁻¹, B⁻¹= 1 3 A f(x) & = 1 3 (x^3-6 x^2+9 x+9 ) f^ (x) & =x^2-4 x+3 aligned Globle maximum at x=6 1 3 (72-72+54+9)=21