One mole of ideal monoatomic gas is taken along a cyclic process as shown in the figure. Process 1 2 shown is 1 / 4^ th part of a circle as shown by dotted line process 2 3 is isochoric while 3 1 is isobaric. If efficiency of the cycle is n % where n is an integer. Find n .

Step-by-step solution

W_ net = (2 P₀ v₀ )- (P₀ v₀ )- P₀ v₀ 4 W _ net = P ₀ v ₀- P ₀ v ₀ 4 =(4- ) P ₀ v ₀ 4 ; Put =3.14W_ net = 0.86 4 P₀ v₀=(0.22) (P₀ v₀ ) Q_ 1 2 =(4.5) (P₀ v₀ )+(1.22) (P₀ v₀ )=(5.72) (P₀ v₀ ) Q_ 2 3 =-3 P₀ v₀+0=-3 (P₀ v₀ ) Q_ 3 1 =-1.5 (P₀ v₀ )- (P₀ v₀ )=-2.5 (P₀ v₀ ) Thus efficiency = W_ net + veheat = 0.22 (P₀ v₀ ) (5.72) (P₀ v₀ ) =0.04 Thus efficiency is 4 %