Most Important Selected Qs for JEE AdvancedChemistryElectrochemistry
Paragraph: For an electrode reaction written as aligned & M ^ n + + ne ⁻ M & E _ red = E _ red ^ - RT nF 1 [ M ^ n+ ] (Nernst equation) & = E _ red ^ - 0.0591 n 1 [ M ^ n+ ] at 298 ~K aligned For the cell reaction, a A+b B x X+y Y aligned & E _ cell = E _ cell ^o- RT nF [ X ]^ x [ Y ]^ y [ A ]^ a [ B ]^ b & = E _ cell ^ - 0.0591 n [ X ]^ x [ Y ]^ y [ A ]^ a [ B ]^ b at 298 ~K aligned For pure solids, liquids or gases
Options
- A2.14 V
- B4.28 V
- C6.42 V
- D8.56 V
Correct answer
A. 2.14 V
Step-by-step solution
For 1 mole of O ₂ O ₂ 2 O ²⁻ ( i.e. 2 3 3 O ²⁻ ) Or 4 3 mol of Al to change into Al ⁺³ ions. n=4 Thus, G =- nEF E =- G nF = +827000 4 96500 =2.14 volt