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Most Important Selected Qs for JEE AdvancedChemistryElectrochemistry

Paragraph: For an electrode reaction written as aligned & M ^ n + + ne ⁻ M & E _ red = E _ red ^ - RT nF 1 [ M ^ n+ ] (Nernst equation) & = E _ red ^ - 0.0591 n 1 [ M ^ n+ ] at 298 ~K aligned For the cell reaction, a A+b B x X+y Y aligned & E _ cell = E _ cell ^o- RT nF [ X ]^ x [ Y ]^ y [ A ]^ a [ B ]^ b & = E _ cell ^ - 0.0591 n [ X ]^ x [ Y ]^ y [ A ]^ a [ B ]^ b at 298 ~K aligned For pure solids, liquids or gases

Options

  1. A2.14 V
  2. B4.28 V
  3. C6.42 V
  4. D8.56 V

Correct answer

A. 2.14 V

Step-by-step solution

For 1 mole of O ₂ O ₂ 2 O ²⁻ ( i.e. 2 3 3 O ²⁻ ) Or 4 3 mol of Al to change into Al ⁺³ ions. n=4 Thus, G =- nEF E =- G nF = +827000 4 96500 =2.14 volt

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