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Most Important Selected Qs for JEE AdvancedChemistryElectrochemistry

Given: F _ Fe ^ 3+/ F e ^ =-0.036 ~V , E _ Fe ^ 2+/ F e ^ =-0.439 ~V . The value of standard electrode potential for the change, Fe ³⁺( aq )+ e ⁻ Fe ²⁺( aq ) will be :

Options

  1. A-0.072 V
  2. B0.385 V
  3. C0.770 V
  4. D-0.270 V

Correct answer

C. 0.770 V

Step-by-step solution

aligned & Fe ³⁺+3 e ⁻ Fe ; E ^ =-0.036 ~V & G ₁^ =- nFE ^ =-3 ~F (-0.036)=+0.108 ~F & Also Fe ²⁺+2 e ⁻ Fe ; E ^ =-0.439 ~V & G ₂^ =- nFE E ^ & =-2 ~F (-0.439)=0.878 ~F & To find ^ for Fe ³⁺( aq )+ e ⁻ Fe ²⁺( aq ) & G ^ =- nF E ^ =-1 FE ^ & G ^ = G ₁^ - G ₂^ & G ^ =0.108 ~F =0.878 ~F & - FE ^ =+0.108 ~F -0.878 ~F & E ^ =0.878-0.108=0.77 ~V aligned

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