Calculate the potential of an indicator electrode versus the standard hydrogen electrode, which originally contained 0.1 M MnO ₄⁻ and 0.1 M H ⁺ and which was treated with Fe ⁺² necessary to reduce 90 % of KMnO ₄ to Mn ⁺² E _ MnO ₄⁻ / Mn ⁺²

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Calculate the potential of an indicator electrode versus the standard hydrogen electrode, which originally contained 0.1 M MnO ₄⁻ and 0.1 M H ⁺ and which was treated with Fe ⁺² necessary to reduce 90 % of KMnO ₄ to Mn ⁺² E _ MnO ₄⁻ / Mn ⁺² ^0=1.51 ~V

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Correct answer: D. 1.4

MnO ₄⁻+ Fe ⁺²+8 H ^ Mn ⁺²+ Fe ⁺³ 0.1 M array ll 0.01 M & 0.09 M array So permanganate electrode behave as cathode. E_ c e l l =1.51-0=1.51 Using Nernst's equation :- ( n =5) E _ MnO ₄⁻ / Mn ^ 2 =1.51+ 0.059 5 [ MnO ₄⁻ ] [ H ⁺ ]^8 [ Mn ⁺² ] =1.51+0.11=1.4 ~V

Calculate the potential of an indicator electrode versus the standard hydrogen electrode, which originally contained 0.1 M MnO ₄⁻ and 0.1 M H ⁺ and which was treated with Fe ⁺² necessary to reduce 90 % of KMnO ₄ to Mn ⁺² E _ MnO ₄⁻ / Mn ⁺² ^0=1.51 ~V

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