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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Hyperbola

JEE Advanced · Mathematics · Hyperbola

Eccentricity of the hyperbola whose asymptotes are given by 3 x+2...

Eccentricity of the hyperbola whose asymptotes are given by 3x+2y−5=03 x+2 y-5=0 and 2x−3y−5=02 x-3 y-5=0 is

Options

  1. A2\sqrt{2}
  2. B32\frac{3}{2}
  3. C2
  4. D53\frac{5}{3}

Correct answer

A. 2\sqrt{2}

Step-by-step solution

It is rectangular hyperbola ⇒e=2\Rightarrow \mathrm{e}=\sqrt{2}
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