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Most Important Selected Qs for JEE AdvancedMathematicsHyperbola

If a hyperbola whose foci are (-2,4) and (4,6) touches y -axis then equation of hyperbola is

Options

  1. A(3 x+y-8)^2- (x-3 y+14)^2 4 =20
  2. B(x+3 y-7)^2 2 - (x-3 y+8)^2 8 =1
  3. C(3 x+y-8)^2 2 - (x-3 y+14)^2 8 =1
  4. D(x-3 y+14)^2 2 - (3 x+y-8)^2 8 =20

Correct answer

A. (3 x+y-8)^2- (x-3 y+14)^2 4 =20

Step-by-step solution

aligned & b^2=4 2=8,2 a e= 40 & a^2 e^2=10=b^2+a^2 aligned aligned & a^2=2 & Centre =(1,5) & Equation of transverse axis x-3 y+14=0 aligned Equation of conjugate axis 3 x+y-8=0 Equation of hyperbola = (3 x+y-8)^2 1 - (x-3 y+14)^2 4 =20

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