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If , and are the roots of the equation x^2(p x+q)=r(x+1) . Then the value of determinant | array ccc 1+ & 1 & 1 1 & 1+ & 1 1 & 1 & 1+ array | is

Options

  1. A1+ 1 + 1 + 1
  2. B0
  3. Cnone of these

Correct answer

C. none of these

Step-by-step solution

The given equation is px ^3+ qx ^2- rx - r =0 . Its roots are given , , so we have + + = -q p ; + + =- r p ; = r p . D= (1+ 1 + 1 + 1 )= ( + + + )=0 .

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