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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Hyperbola

JEE Advanced · Mathematics · Hyperbola

Portion of asymptote of hyperbola x^2 a^2 - y^2 ~b^2 =1 (between...

Portion of asymptote of hyperbola x2a2−y2 b2=1\frac{\mathrm{x}^2}{\mathrm{a}^2}-\frac{\mathrm{y}^2}{\mathrm{~b}^2}=1 (between centre and the tangent at vertex) in the first quadrant is cut by the line y+λ(x−a)=0(λy+\lambda(x-a)=0(\lambda is a parameter )) then

Options

  1. Aλ∈R\lambda \in \mathrm{R}
  2. Bλ∈(0,∞)\lambda \in(0, \infty)
  3. Cλ∈(−∞,0)\lambda \in(-\infty, 0)
  4. Dλ∈R−{0}\lambda \in \mathrm{R}-\{0\}

Correct answer

B. λ∈(0,∞)\lambda \in(0, \infty)

Step-by-step solution

Clearly, −λ<0,λ>0-\lambda \lt 0, \lambda\gt0
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