If A and B are square matrices of order 3 where |A|=-2 and |B|=1 then | (A⁻¹ ) adj (B⁻¹ ) adj (2 A⁻¹ ) | is equal to

Step-by-step solution

We have | (A⁻¹ ) adj (B⁻¹ ) adj (2 A⁻¹ ) |= 1 |A| 1 |B|^2 64 |A|^2 = 64 -2 1 4 =-8 (By using | A ⁻¹ |= 1 | ~A | and | adj B |=| B |^ n -1 where n is order of square matrix)