A 0 . 166g sample of an organic compound was digested with conc. H _ 2 SO _ 4 and then distilled with NaOH . The ammonia gas evolved was passed through 50 . 0mL of 0 . 5N H _ 2 SO _ 4 . The used acid required 30 . 0mL

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Correct answer: 63

A 0 . 166g sample of an organic compound was digested with conc. H _ 2 SO _ 4 and then distilled with NaOH . The

Complete acid is not used in the reaction.

Milli eq. of ${NH}_{3} =$ milli eq. of $NaOH$

$= 0 . 25 \times 30$

$= 7 . 5$

Millimole of Nitrogen $= 7 . 5$

${W}_{Nitrogen} = 7 . 5 \times 14 \times {10}^{- 3}$

$= 0 . 105gram$

$%$ of Nitrogen $= \dfrac{0 . 105}{0 . 166} \times 100 = 63 . 25 = 63$

A 0 . 166g sample of an organic compound was digested with conc. H...

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