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Olympiad workbook
Exam
Olympiad workbook
Subject
NSEC
Chapter
Chemical Kinetics

Olympiad workbook · NSEC · Chemical Kinetics

Gas phase reactions (i) and (ii) are of first and second order...

Gas phase reactions (i) and (ii) are of first and second order respectively 2 N2O5→4NO2+O2………(i)2NO+O2→2NO2…………(ii)\begin{aligned} & 2 \mathrm{~N}_2 \mathrm{O}_5 \rightarrow 4 \mathrm{NO}_2+\mathrm{O}_2 \ldots \ldots \ldots \text{(i)} \\ & 2 \mathrm{NO}+\mathrm{O}_2 \rightarrow 2 \mathrm{NO}_2 \ldots \ldots \ldots \ldots \text{(ii)} \end{aligned} Under certain conditions, the rate constants ( k1,k2\mathrm{k}_1, \mathrm{k}_2 ) of (i) and (ii) respectively, have the same numerical value, when the concentrations of the reactants are expressed in mol/dm3\mathrm{mol} / \mathrm{dm}^3. If the concentrations are expressed in mol/mL\mathrm{mol} / \mathrm{mL}, the correct relationship between k1\mathrm{k}_1 and k2\mathrm{k}_2 is

Options

  1. Ak2×10−3=k1\mathrm{k}_2 \times 10^{-3}=\mathrm{k}_1
  2. Bk2×103=k1\mathrm{k}_2 \times 10^3=\mathrm{k}_1
  3. Ck1=k2\mathrm{k}_1=\mathrm{k}_2
  4. Dk1×106=k2\mathrm{k}_1 \times 10^6=\mathrm{k}_2

Correct answer

A. k2×10−3=k1\mathrm{k}_2 \times 10^{-3}=\mathrm{k}_1

Step-by-step solution

No solution
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