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JEE Main 20205 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
5 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2020 · 5 September · Evening Shift · Chemistry · Redox Reactions

The volume, in mL , of 0 . 02 MK _ 2 Cr _ 2 O _ 7 , solution...

The volume, in mLmL, of 0.02MK2Cr2O70 . 02{MK}_{2}{Cr}_{2}{O}_{7}, solution required to react with 0.288g0 . 288g of ferrous oxalate in acidic medium is…………\ldots \ldots \ldots \ldots (Molar mass of Fe=56gmol−1Fe = 56{gmol}^{- 1} )

Correct answer

0

Step-by-step solution

milliequivalent of K2Cr2O7={K}_{2}{Cr}_{2}{O}_{7} = milliequivalent of FeC2O4{FeC}_{2}{O}_{4}

Vm1×0.02×6=0.288144×3×1000{V}_{m1} \times 0 . 02 \times 6 = \dfrac{0 . 288}{144} \times 3 \times 1000
Vm1×0.02×6=2×6{V}_{m1} \times 0 . 02 \times 6 = 2 \times 6
Vm1=100ml{V}_{m1} = 100ml

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