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JEE Main 20207 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2020 · 7 January · Evening Shift · Chemistry · Redox Reactions

Consider the following reactions: NaCl + K_ 2 Cr_ 2 O_ 7 + H_ 2 SO_...

Consider the following reactions:
\text{NaCl} + {\text{K}_{2}{\text{Cr}_{2}{\text{O}_{7} + \mathop{{\text{H}_{2}{\text{SO}_{4}}_{\left(\text{Conc.}\right)} \to \left(\text{A}\right) + side products
\left(A\right) + NaOH \to \left(B\right) +sideproducts<br/>(B)+H2SO4(dilute)+H2O2→(C)+side products<br />\left(B\right) + \mathop{{H}_{2}S{O}_{4}}_{\left(\text{dilute}\right)} + {H}_{2}{O}_{2} \to \left(C\right) + side products
The sum of the total number of atoms in one molecule each of (A),(B)and(C)\left(A\right), \left(B\right) and \left(C\right) is ________

Correct answer

0

Step-by-step solution

(A)=CrO2Cl2\left(A\right) = Cr{O}_{2}C{l}_{2}
(B)=Na2CrO4\left(B\right) = N{a}_{2}Cr{O}_{4}
\left(C\right) = Cr{O}_{5}</p><p>Chromylchloride(CrO2Cl2)</p><p>Chromyl chloride \left({CrO}_{2}{Cl}_{2}\right) can be prepared by the reaction of potassium chromate or potassium dichromate with hydrogen chloride in the presence of sulfuric acid, followed by distillation. The sulfuric acid serves as the dehydration agent.

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