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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2020 · 7 January · Morning Shift · Chemistry · Redox Reactions

Oxidation number of potassium in K _ 2 O, K _ 2 O _ 2 and K O _ 2 ,...

Oxidation number of potassium in K2O,K2O2{K}_{2}O, {K}_{2}{O}_{2} and KO2,K{O}_{2}, respectively, is:Oxidation number of potassium in K _ 2 O, K _ 2 O _ 2 and K O _ 2 , respectively, is:

Options

  1. A+2,+1+ 2, + 1 and +12+ \dfrac{1}{2}
  2. B+1,+1+ 1, + 1 and +1+ 1
  3. C+1,+4+ 1, + 4 and +2+ 2
  4. D+1,+2+ 1, + 2 and +4+ 4

Correct answer

B. +1,+1+ 1, + 1 and +1+ 1

Step-by-step solution

K2OK+1−O−2−K+1{K}_{2} O\overset{+ 1}{K} - \overset{- 2}{O} - \overset{+ 1}{K} oxygen is more E.N. than potassium

K2O2K+1−O−1−O−1−K+1{K}_{2}{O}_{2}\overset{+ 1}{K} - \overset{- 1}{O} - \overset{- 1}{O} - \overset{+ 1}{K}

KO2K{O}_{2}

Oxidation number of potassium in K _ 2 O, K _ 2 O _ 2 and K O _ 2 , respectively, is:
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