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JEE Main201912 Apr 2019Morning ShiftChemistryRedox ReactionsActual

Given: C o 3 + + e - → C o 2 + ; E ° = + 1.81 V P b 3 + + 2 e - → P b 2 + ; E ° = + 1.67 V C e 4 + + e - → C e 3 + ; E ° = + 1.61 V B i 3 + + 3 e - → B i ; E ° = + 0.20 V Oxidizing power of the species will increase in the order:

Options

  1. AC o 3 + < C e 4 + < B i 3 + < P b 4 +
  2. BB i 3 + < C e 4 + < P b 4 + < C o 3 +
  3. CC o 3 + < P b 4 + < C e 3 + < B i 4 +
  4. DC e 4 + < P b 4 + < B i 3 + < C o 3 +

Correct answer

B. B i 3 + < C e 4 + < P b 4 + < C o 3 +

Step-by-step solution

Higher the value of E Red 0 ; higher will be its oxidizing power. Hence correct order is B i + 3 &#60; C e + 4 &#60; P b + 4 &#60; C o + 3

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