JEE Main20198 Apr 2019Morning ShiftChemistryRedox ReactionsActual
In order to oxidize a mixture of one mole of each of F e C 2 O 4 , F e 2 ( C 2 O 4 ) 3 , F e S O 4 and F e 2 ( S O 4 ) 3 in acidic medium, the number of moles of K M n O 4 is:
Options
- A1
- B2
- C3
- D1.5
Correct answer
B. 2
Step-by-step solution
E q . K M n O 4 ⇒ E q . F e S O 4 + E q . F e 2 S O 4 3 + E q F e C 2 O 4 + E q . F e 2 C 2 O 4 3 K M n O 4 ⇒ M n O 4 - 5 e - + 8 H + + M n O 4 - ⇒ M n + 2 + 4 H 2 O V.F = 5 So E q . K M n O 4 ⇒ E q . F e S O 4 + E q . F e C 2 O 4 + E q . F e 2 C 2 O 4 3 n × 5 = 1 × 1 + 1 × 0 + 1 × 3 + 1 × 6 n × 5 = 1 + 3 + 6 n = 10 5 = 2   m o l e