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Exam
Olympiad workbook
Subject
NSEC
Chapter
Chemical Kinetics

Olympiad workbook · NSEC · Chemical Kinetics

The equilibrium constant K for the reversible reaction A=B is 2 ×...

The equilibrium constant KK for the reversible reaction A=BA=B is 2×1032 \times 10^3 at 350K350 K. The rate constants of the forward reaction in the presence and absence of a suitable catalyst at the same temperature are 5×104 s−15 \times 10^4 \mathrm{~s}^{-1} and 4×10−6 s−14 \times 10^{-6} \mathrm{~s}^{-1} respectively. The rate constant of the reverse reaction in the absence of the catalyst is

Options

  1. A2×10−9 s−12 \times 10^{-9} \mathrm{~s}^{-1}
  2. B2.5×10−1 s−12.5 \times 10^{-1} \mathrm{~s}^{-1}
  3. C1.6×10−7 s−11.6 \times 10^{-7} \mathrm{~s}^{-1}
  4. D1.25×10−2 s−11.25 \times 10^{-2} \mathrm{~s}^{-1}

Correct answer

A. 2×10−9 s−12 \times 10^{-9} \mathrm{~s}^{-1}

Step-by-step solution

No Solution (deleted)
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