JEE Main 202622 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 22 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Solutions
JEE Main 2026 · 22 January · Evening Shift · Chemistry · Solutions
At T(K), 100 ~g of 98 \% H_ 2 SO_ 4 (w / w) aqueous solution is...
At of aqueous solution is mixed with 100 g of aqueous solution. What is the mole fraction of in the resultant solution?
(Given : Atomic mass ).
(Assume that temperature after mixing remains constant)
(Given : Atomic mass ).
(Assume that temperature after mixing remains constant)
Options
- A0.663
- B0.9
- C0.337
- D0.1
Correct answer
C. 0.337
Step-by-step solution
Molar mass of H₂SO₄ = 98 g/mol.
Solution 1: 100 g at 98% gives 98 g H₂SO₄ = 1 mol; water = 2 g = 0.111 mol.
Solution 2: 100 g at 49% gives 49 g H₂SO₄ = 0.5 mol; water = 51 g = 2.833 mol.
Mixed solution: Total H₂SO₄ = 1 + 0.5 = 1.5 mol.
Total water = 0.111 + 2.833 = 2.944 mol.
Mole fraction of H₂SO₄ = 1.5/(1.5 + 2.944) = 1.5/4.444 = 0.337.
Solution 1: 100 g at 98% gives 98 g H₂SO₄ = 1 mol; water = 2 g = 0.111 mol.
Solution 2: 100 g at 49% gives 49 g H₂SO₄ = 0.5 mol; water = 51 g = 2.833 mol.
Mixed solution: Total H₂SO₄ = 1 + 0.5 = 1.5 mol.
Total water = 0.111 + 2.833 = 2.944 mol.
Mole fraction of H₂SO₄ = 1.5/(1.5 + 2.944) = 1.5/4.444 = 0.337.