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JEE Main 202622 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2026 · 22 January · Morning Shift · Chemistry · Solutions

Consider a solution of CO_ 2 (~g) dissolved in water in a closed...

Consider a solution of CO2( g)\mathrm{CO}_{2}(\mathrm{~g}) dissolved in water in a closed container. Which one of the following plots correctly represents variation of \log (partial pressure of CO2\mathrm{CO}_{2} in vapour phase above water) [y[y-axis] with log⁡\log (mole fraction of CO2\mathrm{CO}_{2} in water) [x[x-axis ]] at 25∘C25^{\circ} \mathrm{C} ?Consider a solution of CO_ 2 (~g) dissolved in water in a closed container. Which one of the following plots correctlyConsider a solution of CO_ 2 (~g) dissolved in water in a closed container. Which one of the following plots correctlyConsider a solution of CO_ 2 (~g) dissolved in water in a closed container. Which one of the following plots correctlyConsider a solution of CO_ 2 (~g) dissolved in water in a closed container. Which one of the following plots correctly

Options

  1. AWhich one of the following molecules has maximum dipole moment?
  2. BWhich one of the following molecules has maximum dipole moment?
  3. CWhich one of the following molecules has maximum dipole moment?
  4. DWhich one of the following molecules has maximum dipole moment?

Correct answer

B. Which one of the following molecules has maximum dipole moment?

Step-by-step solution

According to Henry's Law, the partial pressure of a gas in the vapour phase (pp) is proportional to the mole fraction of the gas in the solution (xx).
The mathematical expression is: p=KH⋅xp = K_H \cdot x
where KHK_H is the Henry's law constant.
Taking logarithm on both sides:
log⁡(p)=log⁡(KH⋅x)\log(p) = \log(K_H \cdot x)
log⁡(p)=log⁡(KH)+log⁡(x)\log(p) = \log(K_H) + \log(x)
Comparing this with the equation of a straight line y=mx+cy = mx + c:
y=log⁡(p)y = \log(p) (y-axis)
x=log⁡(x)x = \log(x) (x-axis)
m=1m = 1 (slope)
c=log⁡(KH)c = \log(K_H) (y-intercept)
Since KHK_H for CO2CO_2 in water is a positive constant at 25∘C25^{\circ}C, log⁡(KH)\log(K_H) will be a constant intercept.
The plot of log⁡(p)\log(p) vs log⁡(x)\log(x) is a straight line with a positive slope and a positive y-intercept.
This corresponds to graph (2).
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