JEE Main 20257 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 7 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Solutions
JEE Main 2025 · 7 April · Evening Shift · Chemistry · Solutions
Match List-I with List-II List-I List-II (A) Solution of chloroform...
Match List-I with List-II
Choose the correct answer from the options given below :
| List-I | List-II | ||
| (A) | Solution of chloroform and acetone | (I) | Minimum boiling azeotrope |
| (B) | Solution of ethanol and water | (II) | Dimerizes |
| (C) | Solution of benzene and toluene | (III) | Maximum boiling azeotrope |
| (D) | Solution of acetic acid in benzene | (IV) | \Delta V_{mix }=0 |
Choose the correct answer from the options given below :
Options
- A(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- B(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
A. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Step-by-step solution
(A) Solution of chloroform and acetone shows -ve deviation, so maximum boiling azeotrope.(B) Solution of ethanol \& water shows +ve deviation. So minimum boiling azeotrope.(C) Solution of benzene and toluene form ideal solution. .(D) Acetic acid in benzene form dimer.