JEE Main20257 Apr 2025Evening ShiftChemistrySolutionsActual
Match List-I with List-II array |l|l|l|l| & List-I & & List-II (A) & array l Solution of chloroform and acetone array & (I) & array l Minimum boiling azeotrope array (B) & array l Solution of ethanol and water array & (II) & Dimerizes (C) & array l Solution of benzene and toluene array & (III) & array l Maximum boiling azeotrope array (D) & array l Solution of acetic acid in benzene array & (IV) & V _ mix =0 array Ch
Options
- A(A)-(III), (B)-(I), (C)-(IV), (D)-(II)
- B(A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- C(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- D(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
Correct answer
A. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Step-by-step solution
(A) Solution of chloroform and acetone shows -ve deviation, so maximum boiling azeotrope. (B) Solution of ethanol & water shows +ve deviation. So minimum boiling azeotrope. (C) Solution of benzene and toluene form ideal solution. V _ mix =0 . (D) Acetic acid in benzene form dimer.