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Molality of an aqueous solution of urea is (4.44 ~m ). Mole fraction of urea in solution is (x 10⁻³ ). Value of (x ) is ( ) - (Integer answer)

Correct answer

74

Step-by-step solution

Molality of urea is 4.44 ~m , that means 4.44 moles of urea present in 1000 gm of water. X _ ura = 4.44 4.44+ 1000 18 =0.0740 OR aligned & 74 10⁻³ & X=74 aligned

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