Molality of an aqueous solution of urea is (4.44 ~m). Mole fraction of urea in solution is (x × 10^ -3 ). Value of x is ( ) - (Integer answer)

Correct answer: 74 Molality of urea is 4.44 ~m , that means 4.44 moles of urea present in 1000 gm of water. X_ ura =(4.44)/(4.44+(1000)/(18)) =0.0740 OR aligned & 74 × 10^ -3 & X=74 aligned

JEE Main 20248 AprilEvening Shift

Exam: JEE Main
Year: 2024
Date: 8 April
Shift: Evening Shift
Subject: Chemistry
Chapter: Solutions

JEE Main 2024 · 8 April · Evening Shift · Chemistry · Solutions

Molality of an aqueous solution of urea is (4.44 ~m). Mole fraction...

Molality of an aqueous solution of urea is (4.44 \mathrm{~m}). Mole fraction of urea in solution is (x \times 10^{-3}). Value of

x

is (\qquad) - (Integer answer)

Correct answer

Step-by-step solution

Molality of urea is

4.44 \mathrm{~m}

, that means 4.44 moles of urea present in

1000 \mathrm{gm}

of water.

\therefore \mathrm{X}_{\text{ura }}=\frac{4.44}{4.44+\frac{1000}{18}} =0.0740 OR

\begin{aligned} & 74 \times 10^{-3} \\ & X=74\end{aligned}

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