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(2.5 ~g ) of a non-volatile, non-electrolyte is dissolved in (100 ~g ) of water at (25^ C ). The solution showed a boiling point elevation by (2^ C ). Assuming the solute concentration is negligible with respect to the solvent concentration, the vapor pressure of the resulting aqueous solution is ( ) ( mm ) of ( Hg ) (nearest integer) [Given : Molal boiling point elevation constant of water ( ( K _ b )=0.52 ~K . kg m

Correct answer

0

Step-by-step solution

aligned & 2=0.52 m & m = 2 0.52 aligned According to question, solution is much diluted aligned & so P P ^ = n _ solute n _ solvent & P P ^ = m 1000 M _ solvent & P = P ^ m 1000 M _ solvent & =760 2 0.52 1000 18=52.615 & P ₅=760-52.615=707.385 ~mm of Hg aligned

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