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Mass of ethylene glycol (antifreeze) to be added to 18 . 6 kg of water to protect the freezing point at - 24 ° C is kg (Molar mass in gmol - 1 for ethylene glycol 62 , K f of water = 1 . 86 K kg mol - 1 )

Correct answer

0

Step-by-step solution

Given, ΔT f = - 24 0 C Molar mass of Ethylene glycol= 62 ΔT f = i K f × molality 24 = ( 1 ) × 1 . 86 × W 62 × 18 . 6 W = 14880 gm = 14 . 880 kg

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