We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’ and ‘ C ’ with concentration 0 . 1M, 0 . 01M and 0 . 001M, respectively. The value of van t ’ Haft factor (i) for these solutions will be in the order.

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Correct answer: A. i _ A < i _ B < i _ C

It is because the extent or degree of dissociation increases with increase in dilution of a solution. $0 . 001MNaCl$ solution $' C '$ is most diluted as compared to the other two $NaCl$ solutions. The vant Hoff factor (i) depends on extent of dilution.This confirms answer at (i) ${i}_{A} < {i}_{B} < {i}_{C}$

We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’ and ‘ C ’ with concentration 0 . 1M, 0 . 01M and 0 .

We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’...

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