JEE Main20241 Feb 2024Morning ShiftChemistrySolutionsActual
We have three aqueous solutions of NaCl labelled as ‘ A ’ , ‘ B ’ and ‘ C ’ with concentration 0 . 1 M , 0 . 01 M and 0 . 001 M , respectively. The value of van t ’ Haft factor i for these solutions will be in the order.
Options
- Ai A < i B < i C
- Bi A < i C < i B
- Ci A = i B = i C
- Di A > i B > i C
Correct answer
A. i A < i B < i C
Step-by-step solution
It is because the extent or degree of dissociation increases with increase in dilution of a solution. 0 . 001 M N a C l solution ' C ' is most diluted as compared to the other two N a C l solutions. The vant Hoff factor (i) depends on extent of dilution.This confirms answer at (i) i A < i B < i C