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JEE Main 202311 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 11 April · Morning Shift · Chemistry · Solutions

0 . 004M K _ 2 SO _ 4 solution is isotonic with 0 . 01M glucose...

0.004MK2SO40 . 004M{K}_{2}{SO}_{4} solution is isotonic with 0.01M0 . 01M glucose solution. Percentage dissociation of K2SO4{K}_{2}{SO}_{4} is _____ (Nearest integer)

Correct answer

0

Step-by-step solution

Osmotic pressure π=iCRT\pi = iCRT

i=i =Van't Hoff Factor

C=C =Molarity

R=R =Same gas constant

T=T =Temperature

For isotonic solutions, osmotic pressure are equal, Hence, we have

(0.004)×i=0.01( 0 . 004 ) \times i = 0 . 01

⇒i=0.010.004⇒ i = \dfrac{0 . 01}{0 . 004}

=104=52=1+2α= \dfrac{10}{4} = \dfrac{5}{2} = 1 + 2\alpha

2α=1.52\alpha = 1 . 5

α=0.75\alpha = 0 . 75

% \alpha = 75

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