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JEE Main 20236 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 6 April · Evening Shift · Chemistry · Solutions

Consider the following pairs of solution which will be isotonic at...

Consider the following pairs of solution which will be isotonic at the same temperature. The number of pairs of solutions is/ are _____

A. 1Maq.NaCl1Maq . NaCl and 2Maq.2Maq . urea

B. 1Maq.CaCl21Maq . {CaCl}_{2} and 1.5Maq.KCl1 . 5Maq . KCl

C. 1.5Maq.AlCl31 . 5Maq . {AlCl}_{3} and 2Maq.Na2SO42Maq . {Na}_{2}{SO}_{4}

D. 2.5Maq.KCl2 . 5Maq . KCl and 1Maq.Al2(SO4)31Maq . {Al}_{2} ( {SO}_{4}{)}_{3}

Correct answer

0

Step-by-step solution

A solution having the same solute and solvent concentration as a cell across the semipermeable membrane is referred to as isotonic solution.

The effective concentration of each solution can be calculated as follows,

Effective concentration =i(Von′tHofffactor)×C= i ( {Von}^{'}tHofffactor ) \times C

1MNaCl1MNaCl has effective concentration =2×1=2M= 2 \times 1 = 2M and hence it is isotonic with two molar urea solution.

1MCaCl21M{CaCl}_{2} has effective concentration =3Mand1.5MKCl= 3Mand1 . 5MKCl has also 3M3M, hence, both are isotonic.

1.5MAlCl3≅6Mand2MNa2SO4≅6M1 . 5M{AlCl}_{3} ≅ 6Mand2M{Na}_{2}{SO}_{4} ≅ 6M, Hence both are isotonic.

2.5MKCl≅5Mand1MAl2(SO4)3≅5M2 . 5MKCl ≅ 5Mand1M{Al}_{2}{\left({SO}_{4}\right)}_{3} ≅ 5M, Hence both are isotonic.

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