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Mass of Urea NH 2 CONH 2 required to be dissolved in 1000 g of water in order to reduce the vapour pressure of water by 25 % is _______ g . (Nearest integer) Given : Molar mass of N , C , O and H are 14 , 12 , 16 and 1 g mol - 1 respectively.

Correct answer

0

Step-by-step solution

Relative lowering of vapour pressure = Mole fraction of solute Lowering   of   vapour   pressure Vapoure   pressure   of   solution = moles   of   solute moles   of   solvent 25 75 =  moles of urea  1000 18 1 3 × 1000 18 = moles of urea Mass of urea = 1 3 × 1000 18 × 60 = 1111 . 11   gm

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